Except everyone writing C is writing sloppy C. It’s like driving a car, there’s always a non-zero chance of an accident.
Even worse, in C the compiler is just waiting for you to trip up so it can do something weird. Think the risk of UB is overblown? I found this article from Raymond Chen enlightening: https://devblogs.microsoft.com/oldnewthing/20140627-00/?p=633
A compiler making assumptions like that about undefined behaviour sounds just like a bug. Maybe the bug is in the spec rather than the compiler, but I can’t think of any time it would be better to optimize that code out entirely because UB is detected rather than just throwing an error or warning and otherwise ignoring the edge cases where the behaviour might break. It sounds like the worst possible option exactly for the reasons listed in that blog.
The thing about UB is that many optimizations are possible precisely because the spec specified it as UB. And the spec did so in order to make these optimizations possible.
Codebases are not 6 lines long, they are hundreds of thousands. Without optimizations like those, many CPU cycles would be lost to unnecessary code being executed.
If you write C/C++, it is because you either hate yourself or the application’s performance is important, and these optimizations are needed.
The reason rust is so impressive nowadays is that you can write high performing code without risking accidentally doing UB. And if you are going to write code that might result in UB, you have to explicitly state so with unsafe. But for C/C++, there’s no saving. If you want your compiler to optimize code in those languages, you are going to have loaded guns pointing at your feet all the time.
I recently came across a rust book on how pointers aren’t just ints, because of UB.
fnmain() {
a = &1
b = &2
a++
if a == b {
*a = 3print(b)
}
}
This may either: not print anything, print 3 or print 2.
Depending on the compiler, since b isn’t changed at all, it might optimize the print for print(2) instead of print(b). Even though everyone can agree that it should either not print anything or 3, but never 2.
Yep but not if you write sloppy C code. Gotta keep those nuts and bolts tight!
If you’re writing sloppy C code your assembly code probably won’t work either
Except everyone writing C is writing sloppy C. It’s like driving a car, there’s always a non-zero chance of an accident.
Even worse, in C the compiler is just waiting for you to trip up so it can do something weird. Think the risk of UB is overblown? I found this article from Raymond Chen enlightening: https://devblogs.microsoft.com/oldnewthing/20140627-00/?p=633
A compiler making assumptions like that about undefined behaviour sounds just like a bug. Maybe the bug is in the spec rather than the compiler, but I can’t think of any time it would be better to optimize that code out entirely because UB is detected rather than just throwing an error or warning and otherwise ignoring the edge cases where the behaviour might break. It sounds like the worst possible option exactly for the reasons listed in that blog.
The thing about UB is that many optimizations are possible precisely because the spec specified it as UB. And the spec did so in order to make these optimizations possible.
Codebases are not 6 lines long, they are hundreds of thousands. Without optimizations like those, many CPU cycles would be lost to unnecessary code being executed.
If you write C/C++, it is because you either hate yourself or the application’s performance is important, and these optimizations are needed.
The reason rust is so impressive nowadays is that you can write high performing code without risking accidentally doing UB. And if you are going to write code that might result in UB, you have to explicitly state so with
unsafe. But for C/C++, there’s no saving. If you want your compiler to optimize code in those languages, you are going to have loaded guns pointing at your feet all the time.I recently came across a rust book on how pointers aren’t just ints, because of UB.
fn main() { a = &1 b = &2 a++ if a == b { *a = 3 print(b) } }This may either: not print anything, print 3 or print 2.
Depending on the compiler, since b isn’t changed at all, it might optimize the print for
print(2)instead ofprint(b). Even though everyone can agree that it should either not print anything or 3, but never 2.I hope you are not argueing that using assembly is an improvement over using C in that regard…