Yeah but did you know he worked for Blizzard tho
Oh shit, gotta check the negative numbers as well!
You can do that more efficiently by using abs(number).
Oh. I thought that was Elixir until I zoomed in.
I am more amazed that he didn’t stop at 10 and think “damn this is tiresome isn’t there a one liner i could do?”. I want to know how far he went. His stubbornness is amazing but also scary. I haven’t seen this kind of code since back in school lol lol lol
This is why this code is good. Opens MS paint. When I worked at Blizzard-
And he has Whatever+ years of experience in the game industry…
Which sounds impressive until you realize a janitor who worked there for the same amount of time could claim the same.
I want to assess coders by lines written! The more the better!
Would this be a case of modulo saving the day?
Like: If Number modulo 2 = 0, true
This has to be taken out of context
well that’s the joke, isn’t it
I mean, is it a joke? Because i have no context other than, after making a bad opinion known, there is a lot of talk about his code being terrible. So i guess this is fabricated then yea?
oh. is it assumed we know who the person is? i have no idea who that is.
He’s Thor, worked for blizzard entertainment, indie dev, has a Ferret sanctuary, knows cyber security. Seems like a cool enough guy i guess, has incorrect opinion on video game preservation.
no unit tests huh.
/s
Good if you are rated by an AI that pays for LOCs.
def is_even(n: int) -> bool: if n < 0: return is_even(-n) r = True for _ in range(n): r = not r return rCould also be done recursive, I guess?
boolean isEven(int n) { if (n == 0) { return true; } else { return !isEven(Math.abs(n - 1)); } }deleted by creator
He loves me, he loves me not
No, no, I would convert the number to a string and just check the last char to see if it was even or not.
This code would run a lot faster as a hash table look up.
I agree. Just need a table of even numbers. Oh and a table of odd numbers, of course, else you cant return the false… duh.
In a Juliana tree, or a dictionary tree if you want. For speed.
Y’all laugh but this man has amazing code coverage numbers.
This is YandereDev levels of bad.
this is yanderedev.
no the code is
Thanks to goodness, finally. A (giggle & snort) solid algorithm. There ya’s go set yer clocks & go get a haircut.
def even(n: int) -> bool: code = "" for i in range(0, n+1, 2): code += f"if {n} == {i}:\n out = True\n" j = i+1 code += f"if {n} == {j}:\n out = False\n" local_vars = {} exec(code, {}, local_vars) return local_vars["out"]scalable version
Not even else if? Damn, I guess we’re checking all the numbers every time then. This is what peak performance looks like
O(1) means worst and best case performance are the same.
