0x4E4F@infosec.pub to Programmer Humor@programming.devEnglish · 2 months agoNot my problem sortinfosec.pubimagemessage-square70fedilinkarrow-up1765arrow-down114
arrow-up1751arrow-down1imageNot my problem sortinfosec.pub0x4E4F@infosec.pub to Programmer Humor@programming.devEnglish · 2 months agomessage-square70fedilink
minus-squarexmunk@sh.itjust.workslinkfedilinkarrow-up97·2 months agoGuaranteed to sort the list in nearly instantaneous time and with absolutely no downsides that are capable of objecting.
minus-squarevithigar@lemmy.calinkfedilinkarrow-up16·2 months agoExcept you missed a bug in the “check if it’s sorted” code and it ends up destroying every universe.
minus-squaredb2@lemmy.worldlinkfedilinkarrow-up7·2 months agoThere’s a bug in it now, that’s why we’re still here.
minus-squarefrezik@midwest.sociallinkfedilinkarrow-up48·2 months agoYou still have to check that it’s sorted, which is O(n). We’ll also assume that destroying the universe takes constant time.
minus-squareBatmanAoD@programming.devlinkfedilinkarrow-up44·2 months agoIn the universe where the list is sorted, it doesn’t actually matter how long the destruction takes!
minus-squaregroet@feddit.orglinkfedilinkEnglisharrow-up13·2 months agoIt actually takes a few trillion years but its fine because we just stop considering the “failed” universes because they will be gone soon™ anyway.
minus-squareBenjaben@lemmy.worldlinkfedilinkarrow-up9·2 months ago We’ll also assume that destroying the universe takes constant time. Well yeah just delete the pointer to it!
Guaranteed to sort the list in nearly instantaneous time and with absolutely no downsides that are capable of objecting.
Except you missed a bug in the “check if it’s sorted” code and it ends up destroying every universe.
There’s a bug in it now, that’s why we’re still here.
You still have to check that it’s sorted, which is O(n).
We’ll also assume that destroying the universe takes constant time.
In the universe where the list is sorted, it doesn’t actually matter how long the destruction takes!
amortized O(0)
It actually takes a few trillion years but its fine because we just stop considering the “failed” universes because they will be gone soon™ anyway.
Eh, trillion is a constant
Well yeah just delete the pointer to it!
universe.take()deleted by creator